167 ^ in java does not mean to raise to a power. It means XOR. You can use java's Math.pow() And you might want to consider using double instead of int —that is:

Guava's math libraries offer two methods that are useful when calculating exact integer powers: pow(int b, int k) calculates b to the kth the power, and wraps on overflow checkedPow(int b, int k) is identical …

Nov 17, 2013 · import static java.lang.Math.pow; in the import statements at the top of your code. See the Java Language Specification, section 7.5.3 for details of how this works.

Mar 25, 2016 · Math.pow uses doubles as it produces both large and tiny numbers depending on the inputs. e.g. even 4^20 will not fit in an int. If you want to round the result to a long you can use …

Apr 23, 2011 · ^ is the bitwise exclusive OR (XOR) operator in Java (and many other languages). It is not used for exponentiation. For that, you must use Math.pow.

I got as far as calculating the user's monthly interest rate based on their input, and also began translating my professor's formula into Java's language. However, I can't figure out how to use the …

Dec 17, 2012 · The ^ operator is not performing exponentiation - it's a bitwise "exclusive OR" (aka "xor"). Using integer math for 100000000 raised to the fourth power will give incorrect results - a 32-bit …

I'll use Java as an example here, as it may be completely language-specific, but I'm generally interested in ways to do this. Of course, the simplest and obvious way is this: Math.pow(10, x) but a...

May 2, 2015 · I'm having trouble figuring out when to use int, double and long. I'm working on calculating the power of an integer and return the result as long as the power provided is not a negative number. ...

Jul 7, 2016 · But if I simply use Math.pow(number,1.0/3.0) it works for much bigger numbers and computes it in no time. So, what is the algorithm that Math.pow() uses that gives an instant answer? I …